Part A What is the charge on each capacitor in the figure if

Part A

What is the charge on each capacitor in the figure, if V = 7.0 V ?(Figure 1)

Enter your answers numerically separated by commas.

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Part B

What is the potential difference across each capacitor in the figure?

Enter your answers numerically separated by commas.

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Solution

a) Collapse C2 and C3 are in series

the equivalent capacitor C4

C4 = 1/(1/C2 + 1/C3) = 1/(1/4 + 1/6)

= 2.4 F

C4 and C1 are in parallel

equivalent capacitor C5 =  C1 + C4 = 5 + 2.4 = 7.4 F

C5 in the only element in the circuit with the battery

the total charge on the equivalent capacitor C5 is

Q = CV = (7.4*10^-6F)(7V) = 5.18*10^-5 C

the equivalent capacitors because C4 and C1 are in parallel

Q1 = C1*V = (5 F)(7V) = 35 C

Q4 = C4* = (2.4 F)(7V) = 16.8 C

C2 and C3 they are in series the charge on each is the same.

So, Q2 = Q3 = 16.8 C.

b) the charge on each C1, C2 and C3

Q = CV => V = Q/C

V1 = Q1/C1 = 35C/5 F = 7 V

V2 = Q2/C2 = 16.8 C/4 F = 4.2 V

V3 = Q3/C3 = 16.8 C/6 F = 2.8 V